Question

A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The premium antifreeze solution contains 60% pure antifreeze. The company wants to obtain 240 gallons of mixture that contains 15% pure antifreeze . How many gallons of water and how many gallons of the premium antifreeze solutin must be mixed?

Answer 1

An equation is formed of two equal expressions. The amount of premium antifreeze and the water that should be mixed are 60 gallons and 180 gallons, respectively.

What is an equation?

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Let the amount of premium anti-freeze solution mixed be represented by x, while the amount of water mixed be represented by y.

Since the total mixture should be 240 gallons, therefore,

x + y = 240

Solving for y,

y = 240 - x

Given the percentage of pure antifreeze, the mixture should contain is 15%. Therefore, we can write,

60%x + 0%y = 15%(240)

0.60x = 0.15(240)

x = 60 gallons

Now substitute the value of x in the first equation,

y = 240 - 60 = 180 gallons

Hence, the amount of premium antifreeze and the water that should be mixed are 60 gallons and 180 gallons, respectively.

Learn more about Equation:

https://brainly.com/question/2263981

#SPJ1