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The equation of the graphed function is [tex]y = 3\sec(\frac{\pi}{3}x) + 2[/tex]

How to determine the equation of the graph?

The graph is a secant graph, and it has the following form

[tex]y = a\sec(bx) + c[/tex]


From the graph, we have the following parameters:

  • Local minimum = 5 i.e. the minimum y value in the upper quadrants
  • Local maximum = -1 i.e. the maximum y value in the lower quadrant
  • Time, T = 6 i.e. the difference between corresponding points on the curve

The amplitude (a) is calculated using:

a = 0.5 *(Local minimum - Local maximum)

a = 0.5 *(5 + 1) = 3

The vertical shift (c) is calculated using:

a = 0.5 *(Local minimum + Local maximum)

a = 0.5 *(5 - 1) = 2

The period (b) is calculated using:

[tex]b = \frac{2\pi}{T}[/tex]

This gives

[tex]b = \frac{2\pi}{6}[/tex]

Evaluate

[tex]b = \frac{\pi}{3}[/tex]

Substitute the values of a, b and c in [tex]y = a\sec(bx) + c[/tex]

[tex]y = 3\sec(\frac{\pi}{3}x) + 2[/tex]

Hence, the equation of the graphed function is [tex]y = 3\sec(\frac{\pi}{3}x) + 2[/tex]

Read more about graphs at:

https://brainly.com/question/4025726

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