Question

Find the remainder when 2x^3-5x^2+x-3 is divided by (x-1)

Answer 1

Answer:

-7.

Step-by-step explanation:

Using the Remainder Theorem :

If  f(x) is divided by x-1 then the remainder is f(1), so

The required remainder

= f(1) =  2(1)^3 - 5(1)^2 + (-1) - 3

= 2 - 5 - 1 - 3

= -7.

Answer 2

Answer:

remainder = -5

Step-by-step explanation:

Divide using long division:

$\large \begin{array}{r}2x^2-3x-2\phantom{)}\\x-1{\overline{\smash{\big)}\,2x^3-5x^2+x-3\phantom{)}}}\\\underline{-~\phantom{(}(2x^3-2x^2)\phantom{-b))))))}}\\0-3x^2+x-3\phantom{)}\\ \underline{-~\phantom{()}(-3x^2+3x)\phantom{-b}}\\ 0-2x-3\phantom{)}\\\underline{-~\phantom{()}(-2x+2)}\\ -5\end{array}$