Answer:
C. -18
Step-by-step explanation:
The value of the expression is found by substituting the given value for the variable and following the Order of Operations to evaluate it.
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[tex]\dfrac{2(4(6-t)^2+t-3(t+5))}{3}\qquad\text{given}\\\\=\dfrac{2(4(6-6)^2+6-3(6+5))}{3}=\dfrac{2(4(0^2)+6-3(11))}{3}=\dfrac{2(6-33)}{3}\\\\=\dfrac{2(-27)}{3}=\dfrac{-54}{3}=\boxed{-18}[/tex]
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Additional comment
In this instance, the Order of Operations can be shortcut a bit by factoring 3 from the numerator and denominator early in the evaluation.
= 2(2 -11) = 2(-9) = -18
