Question

In a cage there are 10 rabbits between males and females. 4 of them escape. What is the probability that 3 are female and only one is a male? There are originally 6 females and 4 males.

Please give answer in fraction and not percentage!

Answer 1

Answer:

$\frac{8}{21}$

Step-by-step explanation:

let S be the sample space for this experiment.

card(S) = 10C4 = 210

Let E be the event “having 3 female and only one  male”

card(E) = 6C3 × 4C1 = 80

therefore

p(having 3 female and only one male escaped) is 80/210

$\frac{80}{210} =\frac{8}{21}$