Question

What volume of oxygen gas is needed for the complete combustion of 40.0 liters of hydrogen gas?

Answer 1

Answer:

2C2H6 + 7O2 ==> 4CO2 + 6H2O

When dealing with gases, it is possible to use liters and mols interchangeably.

So 4.00 L C2H6 x (7 mols O2/2 mols C2H6) = 4.00 x 7/2 = ? L O2

Explanation: