Question

pls help me my homework​

Answer 1

Answer:

$1.\; \boxed{\sf x=12^o}$

$\sf 2.\;\boxed{\sf \angle 2=60^o}$

Step-by-step explanation:

1)

Since ∠1 and ∠ (7x-20) are corresponding angle.

So, ∠1 =∠ (7x-20)

and, ∠1 and ∠(5x+16) are vertically opposite angles.

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S0...

$\sf 4x+16=7x-20$

Subtract 16 from both sides.

$\sf 4x=7x-36$

Subtract 7x from both sides.

$\sf 4x-7x=7x-36-7x$

$\sf -3x=-36$

Divide both sides by -3.

$\sf \cfrac{-3x}{-3}=\cfrac{-36}{-3}$

$\boxed{\sf x=12^o}$

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2)

∠1 and ∠2 are corresponding angles.

S0,

$\sf \angle 1=\angle 2=\boxed{\sf 60^o}$

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Additional info:-

Any pair of angles on the same side of one of two lines cut by a transversal and on the same side of the transversal are called corresponding angles.

Vertical angles are angles opposite each other where two lines cross.

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Answer 2

Answer:

x = 12

Step-by-step explanation:

The angles are equal as they are alternate exterior angles.

Solving :

⇒ 4x + 16 = 7x - 20

⇒ 7x - 4x = 16 + 20

⇒ 3x = 36

⇒ x = 12