Pls help me if u can

This is a statistics problem involving Group Frequency Distribution Table. See the attached and the details below.
By dividing observations into intervals and tabulating the frequencies for each interval, data can be organized. A grouped frequency table is the end product.
The intervals in this distribution are referred to as classes.
This is obtained by dividing the sum of the product of all mid points and their frequencies by the total number of observations.
That is Estimated Mean = (f * x)/n ------See the attached sheet.
⇒ 503/50
= 10.06
The median of the 50 observations = 28
This is arrived at by dividing the sum of 25th and the 26th number by 2.
That is (28 + 28)/28=28
This median falls in to the third class - 25-29. Hence, the median group is 25-29.
The estimated median value is computed as follows:
Estimated Median = L + (((n/2)-B)/G) x w
Where :
Inserting the values we have :
L = 25
n = 50
B = 0 + 1 = 1
G = 2
w = 5
Estimated Median = 25 + (((50/2)-1)/2 ) * 5
= 25 + (24/2) * 5
= 85
By observation, the modal group is 30-34. This is because it has the highest frequency of 4.
Hence, the Estimated Mode (EM) is arrived at using the formula:
EM = L + (fₙ-fₙ₋₁)/(fₙ-fₙ₋₁) + (fₙ-fₙ₊₁) x w
where:
Note that
L = 30
fn-1 = 2
fn = 4
fn+1 = 3
w = 5
Hence,
EM = 30 + (4-2)/((4-2) + (4-3)) x 5
= 30 + (2/(2+1)) x 5
= 30 + (2/3) x 5
EM = 33.33
In summary,
Learn more about Group Frequency Distribution at:
https://brainly.com/question/11228919
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