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Just find x

Answer:
x = 50°
Step-by-step explanation:
Let's make 2 equations based on the properties of the triangles :
Applying Exterior Angle Property :
Divide equation 1 by 2 :
⇒ 1/2 (x + 2∠1) = 1/2 x (2∠2)
⇒ x/2 + ∠1 = ∠2
⇒ ∠2 - ∠1 = x/2
Similarly, rewrite equation 2 :
⇒ ∠1 + 25 = ∠2
⇒ ∠2 - ∠1 = 25
From these 2 equations, we get :
⇒ x/2 = 25
⇒ x = 25 × 2
⇒ x = 50°
[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
Let's consider the figure with two triangles,
Angle b is divided into two equal parts :
and similarly
Exterior angle C is divided into two equal parts :
Now, according to exterior Angle property :
In Triangle ABC
[tex]\qquad \sf \dashrightarrow \:2y + x = 2z \: \: \: \: [/tex]
[tex]\qquad \sf \dashrightarrow \: 2z - 2y = x \: \: \: \: [/tex]
[tex]\qquad \sf \dashrightarrow \:2(z - y) = x[/tex]
[tex]\qquad \sf \dashrightarrow \:z - y = \dfrac{x}{2} \: \: \: \: \: \: \: - (1)[/tex]
and in Triangle BDC
[tex]\qquad \sf \dashrightarrow \:y + 25 = z \: \: \: \: \: \: \: [/tex]
[tex]\qquad \sf \dashrightarrow \:z - y = 25 \: \: \: \: \: \: \: - (2)[/tex]
equate equation (1) and (2) :
[tex]\qquad \sf \dashrightarrow \: \dfrac{x}{2} = 25[/tex]
[tex]\qquad \sf \dashrightarrow \: {x}{} = 25 \times 2[/tex]
[tex]\qquad \sf \dashrightarrow \: {x}{} = 50 \degree[/tex]