Question

Two 74.0-kg hockey players skating at 6.15 m/s collide and stick together.

If the angle between their initial directions was 90 ∘ , what is their speed after the collision?

Answer 1

If the angle between their initial directions was 90 ∘ , their speed after the collision will be 4.35 m/s.

What is inelastic collision?

When two moving bodies after colliding stick to each other and move together is called the inelastic collision.

In inelastic collision , momentum is remains conserved.

Initial momentum =Final momentum

m₁u₁ +m₂u₂ = (m₁ +m₂ )v

where, u₁ and u₂ represents initial velocities of two hockey players and v₁ and v₂ shows the final velocities.

m₁ =m₂ =m and u₁ = u₂ =u

Substitute the values from the question, we get

2mu = 2mv

u =v

u = v x cos (θ/2)

u = 6.15 cos(90/2)

u = v = 4.35 m/s

Thus, the speed after collision is 4.35 m/s.

Learn more about inelastic collision.

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