Question

Calculating the Equilibrium Solubility Constant
A specific metal ion, M²+, forms a relatively insoluble sulfide compound, MS, which dissolves to a very limited extent.
MS(s) = M²+ (aq) + S²-(aq)
The concentration of ions in a saturated solution was found:
[M²+ (aq)] = [S2-(aq)] = 0.000143 mol L-¹.
Calculate Ksp for the compound MS.
Give three significant figures.
Enter your answer in exponential form, for example, enter 0.000000672 as 6.72e-7 with no gaps and the -ve e if power
is -ve.

Answer 1

The solubility product of the substance MS in water is 2.0 * 10^-8.

What is solubility product?

The solubility product is an equilibrium constant that shows the extent to which a solid is dissolved in water.

In this case, the equilibrium is; MS(s) = M²+ (aq) + S²-(aq) but M²+ (aq)] = S^2-(aq)] = 0.000143 mol L-¹.

Thus

Ksp = [0.000143 ]^2 = 2.0 * 10^-8

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