Question

Equilibrium Constant Calculation
For the reaction A(g) + B(g) 2 C(g) the following equilibrium concentrations were found:
[A(g)] = 0.232 mol/L
[B(g)] = 0.251 mol/L
[C(g)] = 0.750 mol/L
Calculate the value of the equilibrium constant Ke. Give 3 significant figures in your answer.

Answer 1

The value of the equilibrium constant, Ke given the data from the question is 9.660

What is equilibrium constant?

Equilibrium constant for a given is defined as the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient

For example:

eB <=> cD

The equilibrium constant for the reaction above is given as

Ke = [D]^c / [B]^e

How to determine the equilibrium constant

The following data were obtained from the question:

• A(g) + B(g) <=> 2C(g)
• [A(g)] = 0.232 mol/L
• [B(g)] = 0.251 mol/L
• [C(g)] = 0.750 mol/L
• Equilibrium constant (Ke) =?

The equilibrium constant for the reaction reaction can be obtained as follow

Ke = [C]² / [A][B]

Ke = [0.75]² / [0.232][0.251]

Ke = 9.660

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