Respuesta :
Answer:
d =5
Step-by-step explanation:
d = [tex]\sqrt{(x2-x1)^2 + (y2-y1)^2}[/tex]
at (1,5), (5,2)
d= [tex]\sqrt{(5-1)^2 +(2-5)^2}[/tex]
[tex]d = \sqrt{16 + 9} \\d=\sqrt{25}\\ d =5[/tex]
Therefore 5 is the distance.
Answer:
C
Step-by-step explanation:
calculate the distance d using the distance formula
d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
with (x₁, y₁ ) = (1, 5 ) and (x₂, y₂ ) = (5, 2 )
d = [tex]\sqrt{(5-1)^2+(2-5)^2}[/tex]
= [tex]\sqrt{4^2+(-3)^2}[/tex]
= [tex]\sqrt{16+9}[/tex]
= [tex]\sqrt{25}[/tex]
= 5
