someone help with the answer

The answer is
for parallel : y= 4/7-5x/7
for perpendicular: y=10+7x/5
The slope-intercept form is written as y = mx+b, where m is the slope and b is the y-intercept (the point where the line crosses the y-axis). It's usually easy to graph a line using y=mx+b.
Given line: 5x+7y=9
when our intersection point is (5,-3) the constant
5x+7y
= 5(5)+7(-3)
= 25-21
=4
hence, 5x+7y=4
slope intercept form
7y= 4-5x
y= 4/7-5x/7
Now, for perpendicular lines:
swap the coefficients on x and y with negative sign of x in 5x+7y=9
7x-5y= constant
again, when our intersection point is (5,-3) the constant must be
7x-5y
= 7(5)-5(-3)
=35+15
=50
7x-5y=50
slope intercept form so we solve for y:
y= (50+7x)/5
y=10+7x/5
Learn more about intercept equation here:
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