Find the equation of the line using the point-slope formula. Write the final equation using the slope-intercept form. (x, y) = (−2, 10) and (x, y) = (4, −8) are points on the line

Respuesta :

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[tex]\textsc{heya!}[/tex]

☑︎  what we need to do:

  • find the equation of the line

☑︎ what we are provided with:

  • two points on this line

[tex]\textsc{solution:}[/tex]

  • equation: y=-3x+4

[tex]\textsc{explanation:}[/tex]

first, these are the points on our line:

• (-2, 10) • (4, -8)

what we need at this moment is the gradient (slope) of the line.

remember, there's a little formula that will help us find the gradient:

[tex]\large\text{$\displaystyle\frac{y_2-y_1}{x_2-x_1}$}[/tex]

our values are:

• (-2, 10) and (4, -8)

after substituting the values into the above formula, we obtain

[tex]\large\text{$\displaystyle\frac{-8-10}{4-(-2)}$}[/tex]

after simplifying, we obtain

[tex]\large\text{$\displaystyle\frac{-18}{4+2}$}[/tex]

simplifying more,

[tex]\large\text{$\displaystyle\frac{-18}{6}$}[/tex]

dividing,

[tex]\large\text{$-3$}[/tex]

but that's only part of our problem. we need to find the equation, and we have the gradient only.

let's use the first point in our equation

• (-2, 10)

  • [tex]\large\text{$y-y_1=m(x-x_1)$}[/tex]

m is the gradient.

this is what we obtain after substituting the values

[tex]\large\text{$y-10=-3(x-(-2)$}[/tex]

simplifying

[tex]\large\text{$y-10=-3(x+2)$}[/tex]

simplifying more

[tex]\large\text{$y-10=-3x-6$}[/tex]

moving 10 to the right side

[tex]\large\text{$y=-3x-6+10$}[/tex]

and finally

[tex]\large\text{$y=-3x+4$}[/tex]

[tex]\textsc{hopefully\:helpful}[/tex]

by:    • [tex]\textsc{$d^an_ci^ng$}[/tex]

[tex]\textsc{have\:a\:great\:rest\:of\:your\:day\:ahead!}[/tex]

           

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