Respuesta :
♪ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ♪
[tex]\textsc{heya!}[/tex]
☑︎ what we need to do:
- find the equation of the line
☑︎ what we are provided with:
- two points on this line
[tex]\textsc{solution:}[/tex]
- equation: y=-3x+4
[tex]\textsc{explanation:}[/tex]
first, these are the points on our line:
• (-2, 10) • (4, -8)
what we need at this moment is the gradient (slope) of the line.
remember, there's a little formula that will help us find the gradient:
[tex]\large\text{$\displaystyle\frac{y_2-y_1}{x_2-x_1}$}[/tex]
our values are:
• (-2, 10) and (4, -8)
after substituting the values into the above formula, we obtain
[tex]\large\text{$\displaystyle\frac{-8-10}{4-(-2)}$}[/tex]
after simplifying, we obtain
[tex]\large\text{$\displaystyle\frac{-18}{4+2}$}[/tex]
simplifying more,
[tex]\large\text{$\displaystyle\frac{-18}{6}$}[/tex]
dividing,
[tex]\large\text{$-3$}[/tex]
but that's only part of our problem. we need to find the equation, and we have the gradient only.
let's use the first point in our equation
• (-2, 10)
- [tex]\large\text{$y-y_1=m(x-x_1)$}[/tex]
m is the gradient.
this is what we obtain after substituting the values
[tex]\large\text{$y-10=-3(x-(-2)$}[/tex]
simplifying
[tex]\large\text{$y-10=-3(x+2)$}[/tex]
simplifying more
[tex]\large\text{$y-10=-3x-6$}[/tex]
moving 10 to the right side
[tex]\large\text{$y=-3x-6+10$}[/tex]
and finally
[tex]\large\text{$y=-3x+4$}[/tex]
[tex]\textsc{hopefully\:helpful}[/tex]
by: • [tex]\textsc{$d^an_ci^ng$}[/tex]
[tex]\textsc{have\:a\:great\:rest\:of\:your\:day\:ahead!}[/tex]