Question

If AD=2:5 the coordinates of point F are. Point E has the coordinates (3.8, -3) and the coordinates of point D are

Answer 1

Using the assumed coordinates of point F, the coordinates of point D are (3,3)

How to determine the coordinates of D?

The given parameters are:

Ratio, m : n = 2 : 5

E = (3.8, -3)

The coordinates of point D is calculated using:

$D = \frac{1}{m + n} * (mx_2 +nx_1,my_2 +ny_1)$

So, we have:

$D = \frac{1}{2 + 5} * (2x_2 +5*3.8,2y_2 +5*-3)$

Evaluate the sum and the products

$D = \frac{1}{7} * (2x_2 +18,2y_2 -15)$

Assume the coordinates of point F are:

F = (1.5,18);

The equation becomes

$D = \frac{1}{7} * (2*1.5 +18,2*18 -15)$

Evaluate

$D = \frac{1}{7} * (21,21)$

This gives

D = (3,3)

Hence, the coordinates of point D are (3,3)

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