Question

Can someone help me to solve this question? Prove that the quadrilateral ABCD whose vertices are A(-2,-1), B(-2,-3), C( 5,6), and D(5,-1)is a trapezium.Find the area of trapezium ABCD. Also Can you tell how to find the height of trapezium with vertices without knowing the area? Thank you.

Answer 1

If the height of the trapezium is 7 units. Then the area of the trapezium will be 31.5 square units.

What is a trapezium?

It is a polygon that has four sides. The sum of the internal angle is 360 degrees. In a trapezium, one pair of opposite sides are parallel.

The quadrilateral ABCD whose vertices are A(-2,-1), B(-2,-3), C( 5,6), and D(5,-1).

The lines AB and CD are parallel to the y-axis. Then the quadrilateral ABCD is a trapezium.

The height of the trapezium will be 7 units.

The area of the trapezium will be

Area = 1/2 (2 + 7) x 7

Area = 0.5 x 9 x 7

Area = 31.5 square units.

More about the trapezium link is given below.

https://brainly.com/question/22607187

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