Question

What is the perimeter of rhombus ABCD?
10 units
20 units
2√7 units
4√7 units

Answer 1

Answer:

The perimeter of the rhombus is 20 units

Step-by-step explanation:

One important fact about a rhombus is that all four of its sides are equal, so we only need to solve for one side in order to find the perimeter. We can use the Pythagorean Theorem to solve the side length of the rhombus. Using line AD as a reference, we know that the length of AD is the square root of the change in x squared plus the change in y squared, or $\sqrt{3^{2}+4^{2} } =\sqrt{9+16} =\sqrt{25}=5$ units. Multiply the length of AD by 4 and you'll get that the perimeter of rhombus ABCD is 5 × 4 = 20 un.

Answer 2

Answer:

20 units

Step-by-step explanation:

Finding the side length :

⇒ √(1 + 2)² + (1 - 5)²

⇒ √3² + (-4)²

⇒ √9 + 16

⇒ √25

⇒ 5

Finding the perimeter :

⇒ Perimeter = 4 × side length

⇒ Perimeter = 4 x 5

⇒ Perimeter = 20 units