Question

A body which is uniformly decelerated comes to rest in 5s after travelling of 10m. What is its initial velocity a distance​

Answer 1

Answer:

4 m/s

Explanation:

v=u+ at  and  v^2=u^2+2as.

It is given that  v=0,t=5  s    and  s=10  m.

⇒0=u+5a  and  0=u^2+20a.

⇒a=−u/5  and  a=−u^2/20.

⇒u/5 = u^2/20⇒u=4  m/s.

⇒  The initial velocity is  4  m/s.