Question

PLEASEEE HELP 100 POINTS
Write the equation of a circle whose center is at the origin and that contains the point (-3, 0).

Answer 1

Radius

• √(-3)²+(0)²
• √9
• 3units

So

equation of circle

• (x-h)²+(y-k)²=r²
• (x-0)²+(y-0)²+3²
• x²+y²=9

Answer 2

Answer:

$x^2+y^2=9$

Step-by-step explanation:

Equation of a circle

$(x-a)^2+(y-b)^2=r^2$

(where (a, b) is the center and r is the radius)

Given:

• center = (0, 0)
• point on circle = (-3, 0)

Substitute the given values into the formula and solve for r²:

$\implies (-3-0)^2+(0-0)^2=r^2$

$\implies (-3)^2+(0)^2=r^2$

$\implies 9=r^2$

Substitute the center and found value of r² into the formula to determine the equation of the circle:

$x^2+y^2=9$