Question

An aluminum aerosol can will burst if the pressure inside reaches 210.0 psi. if the can initially contains an ideal gas at 459.5 kpa at 298.15 k, at what temperature (in k) will the can burst?

Answer 1

The can will burst at 938.45 K.

What is Gay Lussac's Law ?

Gay Lussac's Law states that the pressure of a fixed amount of gas is directly proportional to the absolute temperature at constant volume.

i.e. P ∝ T

P= KT

P₁ = KT₁

P₂ = KT₂

Here we have considered that the gas is at two different temperatures and pressures which is denoted by T₁ , T₂ and P₁ , P₂

It can also be written as

(P₁ /P₂ )  = (T₁ / T₂)

It is given that

P₂ = 14.29 atm

P₁  = 4.535 atm

T₁ = 298.15 K

T₂ = ?

T₂ = (298.15 * 14.29 )/ 4.54

T₂ = 938.45 K

Therefore the can will burst at 938.45 K.

To know more about Gay Lussac's Law

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