Question

Type the correct answer in the box. given: cac2 n2 → cacn2 c in this chemical reaction, how many grams of n2 must be consumed to produce 265 grams of cacn2? express your answer to three significant figures. the reaction requires grams of n2.

Answer 1

The amount, in grams, of $N_2$ that will be consumed to produce 265 grams of $CaCN_2$ will be 80.61 grams

Stoichiometric calculation

From the equation of the reaction:

$CaC_2 + N_2 --- > CaCN_2 + C$

The mole ratio of  $N_2$ consumed to   $CaCN_2$ produced is 1:1.

Mole of 265 grams of  $CaCN_2$ = 265/92.11 = 2.88 moles

Equivalent moles of  $N_2$ = 2.88 moles

Mass of 2.88 moles  $N_2$ = 2.88 x 28.02 = 80.61 grams

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