1. 24.76 grams of potassium carbonate (K2CO3) is reacted with an excess of aluminum nitrate (Al(NO3)3) to produce potassium nitrate (KNO3) and aluminum carbonate (Al2(CO3)3). How many grams of the product Al2(CO3)3 is formed? Round to the nearest hundredth.

Respuesta :

Excess reagents are the chemical species that remain after the reaction completion. 14 gms of aluminum carbonate will be formed.

What are grams?

Grams are the unit of the mass that is defined by the product of the moles and the molar mass of the substance.

The balanced chemical reaction is shown as:

3 K₂CO₃ + 2 Al(NO₃)₃ → Al₂(CO₃)₃ + 6 KNO₃

From the reaction, it can be said that 2 moles of aluminum nitrate are required to produce a mole of aluminum carbonate.

Moles of potassium carbonate are calculated as:

Moles = 24.76 gm ÷ 138.205 g/mol = 0.179 moles

If 3 moles of potassium carbonate produce 1 mole of aluminum carbonate, then 0.179 moles will produce 0.059 moles.

From the moles, mass is calculated as:

Mass = moles × molar mass

= 0.059 moles ×  234.08 g/mol

= 13.97 gms

Therefore, 14 gms of aluminum carbonate will be formed.

Learn more about excess reagents here:

https://brainly.com/question/27549432

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