Question

Alexei wants to hang a mirror in his boat and put a frame around it. The mirror and frame must have an area of 19.25 square feet. The mirror is 3 feet wide and 5 feet long. Which quadratic equation can be used to determine the thickness of the frame, x?
2x^2 + 8x − 19.25 = 0

3x^2 + 5x − 19.25 = 0

4x^2 + 16x − 4.25 = 0

4x^2 + 16x + 15 = 0

Answer 1

The quadratic equation 4x² +16x - 4.25 = 0 can be used to determine the thickness of the frame option third is correct.

What is a quadratic equation ?

Any equation of the form $\rm ax^2+bx+c=0$ Where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

We have:

The mirror and frame must have an area of 19.25 square feet. The mirror is 3 feet wide and 5 feet long.

Let's suppose the thickness of the frame is x:

Then, the area of the rectangle:

(2x+3)(2x+5) = 19.25

4x² + 10x + 6x + 15 = 19.25

4x² +16x - 4.25 = 0

Thus, the quadratic equation 4x² +16x - 4.25 = 0 can be used to determine the thickness of the frame option third is correct.

Learn more about quadratic equations here:

brainly.com/question/2263981

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