House numbers along a street consist of two-digit numbers. Each house number is made up of non-zero digits, and no digit in a house number is repeated. Event A is defined as choosing 8 as the first digit, and event B is defined as choosing a number less than 6 as the second digit. If a house number along this street is picked at random, with each number being equally likely and no repeated digits in a number, what is P(A and B) expressed in the simplest form? A. 1/9 B. 5/72 C. 5/8 D. 2/3

Respuesta :

The value of the probability P(A and B) is 5/72 if the house numbers along a street consist of two-digit numbers, option (B) is correct.

What is probability?

It is defined as the ratio of the number of favourable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

Total number of outcomes = 9×8  = 72

(because the total number of digits excluding 0)

Event A: choosing 8 as the first digit

Event B: choosing a number less than 6 as the second digit

Total favourable outcomes = 1×5 = 5

Because there are total 5 digits that are less than 6 {1, 2, 3, 4, 5}

Probability = 5/72

Thus, the value of the probability P(A and B) is 5/72 if the house numbers along a street consist of two-digit numbers option (B) is correct.

Learn more about the probability here:

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Answer:

The answer is B I'm pretty sure.

Step-by-step explanation:

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