Use the general formula for decay substance
[tex]\\ \rm\Rrightarrow N=N_o(1-r)^t[/tex]
For our equation r=62%=0.62
So
function becomes
[tex]\\ \rm\Rrightarrow N=650(1-0.62)^t[/tex]
[tex]\\ \rm\Rrightarrow N=650(0.38)^t[/tex]
Change for a year
[tex]\\ \rm\Rrightarrow N=650(0.38)[/tex]
[tex]\\ \rm\Rrightarrow N=247g[/tex]
Amount decayed=650-247=403g
Daily decay
Percentage decay
[tex]\\ \rm\Rrightarrow \dfrac{1.1}{650}\times 100[/tex]
[tex]\\ \rm\Rrightarrow 0.169[/tex]
[tex]\\ \rm\Rrightarrow 16.9\%[/tex]