Respuesta :

  • 9(x-8)=3(4x-12)
  • 9x-72=12x-37
  • 9x-12x=-72+37
  • -3x=-35
  • x=-35/-3
  • x=35/3

Solving as exponents

[tex]\\ \rm\Rrightarrow 9^{(x-8)}=3^{(4x-12)}[/tex]

[tex]\\ \rm\Rrightarrow 3^{2(x-8)}=3^{2(x-6)}[/tex]

[tex]\\ \rm\Rrightarrow 2(x-8)=2(x-6)[/tex]

[tex]\\ \rm\Rrightarrow 2x-16=4x-12[/tex]

[tex]\\ \rm\Rrightarrow -2x=4[/tex]

[tex]\\ \rm\Rrightarrow x=-2[/tex]

Answer:

[tex]x=-2[/tex]

Step-by-step explanation:

Given equation:

[tex]9^{x-8}=3^{4x-12}[/tex]

Rewrite 9 as 3²:

[tex]\implies (3^2)^{x-8}=3^{4x-12}[/tex]

[tex]\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:[/tex]

[tex]\implies 3^{2(x-8)}=3^{4x-12}[/tex]

[tex]\implies 3^{2x-16}=3^{4x-12}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^{f(x)}=a^{g(x)} \implies f(x)=g(x):[/tex]

[tex]\implies 2x-16=4x-12[/tex]

Subtract 2x from both sides:

[tex]\implies 2x-16-2x=4x-12-2x[/tex]

[tex]\implies -16=2x-12[/tex]

Add 12 to both sides:

[tex]\implies -16+12=2x-12+12[/tex]

[tex]\implies -4=2x[/tex]

Divide both sides by 2:

[tex]\implies \dfrac{-4}{2}=\dfrac{2x}{2}[/tex]

[tex]\implies x=-2[/tex]

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