Respuesta :
- 9(x-8)=3(4x-12)
- 9x-72=12x-37
- 9x-12x=-72+37
- -3x=-35
- x=-35/-3
- x=35/3
Solving as exponents
[tex]\\ \rm\Rrightarrow 9^{(x-8)}=3^{(4x-12)}[/tex]
[tex]\\ \rm\Rrightarrow 3^{2(x-8)}=3^{2(x-6)}[/tex]
[tex]\\ \rm\Rrightarrow 2(x-8)=2(x-6)[/tex]
[tex]\\ \rm\Rrightarrow 2x-16=4x-12[/tex]
[tex]\\ \rm\Rrightarrow -2x=4[/tex]
[tex]\\ \rm\Rrightarrow x=-2[/tex]
Answer:
[tex]x=-2[/tex]
Step-by-step explanation:
Given equation:
[tex]9^{x-8}=3^{4x-12}[/tex]
Rewrite 9 as 3²:
[tex]\implies (3^2)^{x-8}=3^{4x-12}[/tex]
[tex]\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:[/tex]
[tex]\implies 3^{2(x-8)}=3^{4x-12}[/tex]
[tex]\implies 3^{2x-16}=3^{4x-12}[/tex]
[tex]\textsf{Apply exponent rule} \quad a^{f(x)}=a^{g(x)} \implies f(x)=g(x):[/tex]
[tex]\implies 2x-16=4x-12[/tex]
Subtract 2x from both sides:
[tex]\implies 2x-16-2x=4x-12-2x[/tex]
[tex]\implies -16=2x-12[/tex]
Add 12 to both sides:
[tex]\implies -16+12=2x-12+12[/tex]
[tex]\implies -4=2x[/tex]
Divide both sides by 2:
[tex]\implies \dfrac{-4}{2}=\dfrac{2x}{2}[/tex]
[tex]\implies x=-2[/tex]
