Question

A helium balloon possesses a volume of 2500 L at a temperature of 114 °C. What volume will the balloon have if the temperature changes to 56 °C? The pressure remains constant

Answer 1

Given that the pressure remains constant, if the temperature of the helium balloon decreases to the given value, the volume increases to 2125.5L.

What is Charles's law?

Charles's law states that "the volume occupied by a definite quantity of gas is directly proportional to its absolute temperature.

It is expressed as;

V₁/T₁ = V₂/T₂

Given the data in the question;

• Initial temperature of gas T₁ = 114°C = (114+273.15)K = 387.15K

• Initial volume of gas V₁ = 2500L

• Final temperature T₂ = 56°C = (56+273.15)K = 329.15K
• Final volume V₂ = ?

V₁/T₁ = V₂/T₂

V₂ = V₁T₂ / T₁

V₂ = ( 2500L × 329.15K ) / 387.15K

V₂ = 882875LK / 387.15K

V₂ = 2125.5L

Given that the pressure remains constant, if the temperature of the helium balloon decreases to the given value, the volume increases to 2125.5L.

Learn more about Charles's law here: brainly.com/question/12835309

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