The value of the function at the right endpoint of the rectangle is 5 +6k/n.
In the question above;
Th width of the interval is said to be (5 -2) = 3.
So, the width of one of n parts of it = 3/n
To solve for the differences that exist between the left end point of the interval and the value of x at the right end of the k-th rectangle, one can say that:
k·(3/n) = 3k/n
Note that the value of x at shows the point of difference added to the interval's left end and thus it will be: 2 + 3k/n
Therefore, the value of the function for the value of x will be:
f(2 +3k/n) = 2(2 +3k/n) +1 = (4 +6k/n) +1
= 5 +6k/n
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