It should be noted that in the equation y = -3x² + x + 12, there are two real solutions.
It should be noted that the number of real solutions of a quadratic equation is represented by y = ax² + bx - c.
In the equation, equation y = -3x² + x + 12, the coefficients are a = -3, b = 1 and c = 12. The discriminant will be:
= 1² - 4(-4)(12)
= 145
It is positive, therefore, it has two solutions.
Learn more about real solutions on:
https://brainly.com/question/10043755
#SPJ4
