a student was asked to multiply a number by 3/2. instead he divided the number by 3/2 and obtained a number smaller by 2/3, the number is:

Respuesta :

Answer:

[tex]\boxed{\bf \sf number : \ \frac{4}{5} }[/tex]

Explanation:

Let the number be n

According to students Condition:

[tex]\rightarrow \sf \dfrac{3}{2} \ x \ n \quad = \quad \dfrac{3n}{2}[/tex]

What He actually Did:

[tex]\rightarrow \sf n \div \dfrac{3}{2} \quad = \quad n \ x \ \dfrac{2}{3} \quad = \quad \dfrac{2n}{3}[/tex]

He got a smaller number by 2/3, so:

[tex]\rightarrow \sf \dfrac{3n}{2} - \dfrac{2n}{3} = \dfrac{2}{3}[/tex]

make the denominator's same

[tex]\rightarrow \sf \dfrac{3(3n)}{6} - \dfrac{2(2n)}{6} = \dfrac{2}{3}[/tex]

multiply the integers

[tex]\rightarrow \sf \dfrac{9n}{6} - \dfrac{4n}{6} = \dfrac{2}{3}[/tex]

Join the fractions

[tex]\rightarrow \sf \dfrac{9n-4n}{6} = \dfrac{2}{3}[/tex]

Subtract integers

[tex]\rightarrow \sf \dfrac{5n}{6} = \dfrac{2}{3}[/tex]

Cross multiply

[tex]\rightarrow \sf n = \dfrac{6 \ * \ 2}{5 \ * \ 3} \quad = \quad \dfrac{4}{5}[/tex]

Lets see

the number be x

The expression is

  • 3x/2-2x/3=2/3
  • 9x-4x)6=2/3
  • 5x)6=2/3
  • 15x=12
  • x=12/15=4/5
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