Respuesta :

Using the normal distribution, it is found that the desired measures are given by:

a. Z = -0.67.

b. X = 2.2.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In item a, we have that [tex]X = 36, \mu = 40, \sigma = 6[/tex], and want to find Z, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{36 - 40}{6}[/tex]

Z = -0.67.

In item b, we have that [tex]\mu = 1.3, \sigma = 0.6, Z = 1.5[/tex], and want to find X, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.5 = \frac{X - 1.3}{0.6}[/tex]

X - 1.3 = 0.6 x 1.5

X = 2.2.

More can be learned about the normal distribution at https://brainly.com/question/24663213

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