Graph the circle with center (−3, −3) that passes through (2, −3). Find the area in terms of π and to the nearest tenth. Use 3.14 for π.

Respuesta :

[tex]\fcolorbox{red}{blue}{Answer}[/tex]

78.5 units²

Step-by-step explanation:

[tex] \textsf{\large{\underline{To find :-}}}[/tex]

The area of circle on graph

[tex] \textsf{\large{\underline{Given :-}}}[/tex]

[tex] \sf (x_1,y_1) = (-3,-3) \\ \sf (x_2,y_2) = (2,-3)[/tex]

[tex] \textsf{ \huge{\underline{\underline{Solution :-}}}}[/tex]

We can see in the above question that we have been provided the center of thee circle and line of the circle passes through a point.

So to find the radius we have to find the distance between center of circle and the point from which line passes.

[tex] \sf \blue{ Distance = \sqrt{ {(x_2 - x_1)}^{2} + {(y_2 - y_1)}^{2} } }[/tex]

Now substituting the required values

[tex] \sf \implies\sqrt{ { \{2 - ( - 3) \}}^{2} + { \{ - 3 - ( - 3) \}}^{2} } \\ \\ \sf \implies \sqrt{ {(2 + 3)}^{2} + {( - 3 + 3)}^{2} } \\ \\ \sf \implies \sqrt{ {5}^{2} + {0}^{2} } \\ \\ \sf \implies \sqrt{25} \\ \\ \sf \implies 5 \: units[/tex]

So the radius will be 5 units

Now we will simply formula for area of circle

[tex] \sf \green{ Area \: of \: circle = \pi {r}^{2} }[/tex]

Now substituting the required values

[tex] \sf \hookrightarrow Area = 3.14 \times {5}^{2} \\ \\ \sf \hookrightarrow Area = 3.14 \times 25 \\ \\ \red{\boxed {\hookrightarrow \frak{78.5 \: {units}^{2} } }}[/tex]

Answer:

78.5

Step-by-step explanation:

ACCESS MORE