The formula of the quadratic function passing through the points (-2,0), (8,0) and (2, -24) is f(x) = x² - 6x - 16
How to create the formula?
The points are given as:
(-2,0) , (8,0) and (2, -24)
The points (-2,0) and (8,0) are the zeros of the function.
So, we have:
f(x) = a(x + 2)(x -8)
Substitute (2, -24) in the above equation
-24 = a(2 + 2)(2 -8)
Evaluate the sum and the difference
-24 = a(4)(-6)
Divide both sides by -24
a = 1
Substitute a = 1 in f(x) = a(x + 2)(x -8)
f(x) = (x + 2)(x -8)
Expand
f(x) = x² + 2x - 8x - 16
Evaluate the like terms
f(x) = x² - 6x - 16
Hence, the formula of the quadratic function is f(x) = x² - 6x - 16
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