Question

How much heat is released when 60.0 G of steam at 235°C is converted to water at 100°C?

Answer 1

Answer:12668 J.

Explanation:

First of all, steam is there so in order to convert it into water it must have to release latent heat of vaporization which is equal to approximately 2450 kJ/kg or 2450 J/g.

So, the calculation is given below.

Heat released during conversion of steam at 100°C to water at 100°C= m*L

= 5*2450= 12250 J.

Heat released during conversion of water at 100°C to water at 80°C= m*Cp*(∆T)

= 5*4.18*20= 418 J.

So total heat released= 12668 J.

hope this helps:)!!!