Question

Can someone PLEASE help with these 10th grade geometry angle problems? I have no idea how to solve these and I'm desperate. My teacher won't get back to me and I really need this done. will reward brainly and 5 stars + thanks. You don't have to answer both if you don't want to. either would help tremendously.

Answer 1

Question 1

Given

• m∠MPN = 35°
• mLP = 130°

To find

• The value of mMN

We can see MN is intercepted by the angle MPN.

Inscribed angle is half the measure of intercepted arc

• m∠MPN = 1/2mMN ⇒

• mMN = 2 × m∠MPN = 2 × 35° = 70°

The answer is mMN = 70°

Question 2

Given

• m∠AOB = 40°
• mED = 60°

To find

• m∠COD

See the solution with reasons for each line

• m∠COD = m∠EOB             ⇔ vertical angles are congruent

• mBD = 180°                         ⇔ BD is diameter and cuts the circle in   half

• m∠EOB = mBD - mED        ⇔ Angle addition

• m∠EOB = 180° - 60° = 120° ⇔ Substitution

So the answer is m∠COD = 120°