Question

please help me outttt

Answer 1

Answer:

(-1, 4) and (2, 7)

Step-by-step explanation:

• Graphs f(x) & g (x) are intersecting each other.

• -> f(x) = g(x)

• $\implies x^2+3 =x + 5$

• $\implies x^2+3 -x -5=0$

• $\implies x^2 -x -2=0$

• $\implies x^2 -2x +x-2=0$

• $\implies x(x -2) +1(x-2)=0$

• $\implies (x -2)(x+1)=0$

• $\implies (x -2)=0,\:\: (x+1)=0$

• $\implies x=2\:\: x=-1$

• $\implies x=-1,\:\:2$

• When x = -1

• $f(x) = (-1)^2+3 = 1 +3 = 4$

• -> (x, f(x)) = (-1, 4)

• & When x = 2

• $f(x) = (2)^2+3 = 4 +3 = 7$

• -> (x, f(x)) = (2, 7)

• Thus, the points of intersection of the functions f(x) and g(x) are (-1, 4) and (2, 7)