(a) f(0) in the given function in mod 5 is 2.
(b) f(1) in the given function in mod 5 is 2.
(c) f(2) in the given function in mod 5 is 3.
(d) f(3) in the given function in mod 5 is 1.
(e) f(4) in the given function in mod 5 is 2.
Value of the function in mod 5
The given function is defined as follows;
f(x) = (x³ + 4x + 2) mod 5
f(0) = (0 + 0 +2) = 2 in mod 5 (0 remainder 2) = 2
f(1) = (1 + 4 + 2) = 7 in mod 5 (1 remainder 2) = 2
f(2) = (2³ + 4(2) + 2) = 18 in mod 5 (3 remainder 3) = 3
f(3) = (3³ + 4(3) + 2) = 41 in mod 5 (8 remainder 1) = 1
f(4) = (4³ + 4(4) + 2) = 82 in mod 5 (16 remainder 2) = 2
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