Question

What is the period, in seconds, of a simple pendulum of length 5 meters? Use
the gravitational constant g = 9.8 m/s2 and round your answer to two decimal
places.

Answer 1

$T=2\pi \sqrt{(\frac{l}{g} )} \\T=2\pi \sqrt{\frac{5m}{(9.8m/s^{2}) } }$

$T$ ≈ $4,49s$