Given that measure OAB equals 45. What is the area of the shaded portion of the circle?

Answer:
D. [tex]8\pi-16[/tex]
Step-by-step explanation:
A circle measures 360 degrees and has an area [tex]A=\pi{r}^2[/tex]
The radius (also side length) is given: [tex]4\sqrt{2}[/tex].
The area of this circle is [tex]A=\pi\cdot{4}{\sqrt{2}}^2=32\pi[/tex]
The area of a triangle is (1/2)bh, so this triangle is: [tex](\frac{1}{2})\cdot 4\sqrt{2}\cdot4\sqrt{2}=A[/tex]
Triangle area: A = 16 units^2.
Now, subtract the area of the triangle from 1/4 of the circle's area:
(1/4)32pi - 16 = 8pi - 16