Question

A line passes through the point (-1, - 8) and has a slope of -6. Write an equation for this line.In slope intercept form

Answer 1

      $\rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}$

    A line passes through the point (-1, -8) and has a slope of -6. Write an

     equation for the line in slope-intercept form.

$\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}$

First, let's write the equation of the line in Point-slope form:-

       $\Large\text{ y-y_1=m(x-x_1) }$

Replace y₁ with -8, m with -6, and x₁ with -1:-

          $\Large\text{y-(-8)=-6(x-(-1)}$

$\bigstar$ On simplification,

         $\Large\text{y+8=-6(x+1)}$

$\bigstar$ Now let's convert it into slope-intercept form:-

                     $\Large\text{y+8=-6x-6}$

$\bigstar$ On further simplification,

$\Large\text{y=-6x-6-8}$

$\bigstar$ Finally, We get

$\Large\textit{y=-6x-14}$

$\Uparrow\textsf{Our equation in slope-intercept form}$

Good luck with your studies.

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            $\rule{70}{1}\smile\smile\smile\smile\rule{70}{1}$    

Answer 2

Answer:

y = - 6x - 14

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = - 6 , then

y = - 6x + c ← is the partial equation

to find c substitute (- 1, - 8 ) into the partial equation

- 8 = 6 + c ⇒ c = - 8 - 6 = - 14

y = - 6x - 14 ← equation in slope- intercept form