Question

A 15-kg block of ice is sitting at rest on a frozen lake. A 3-kg
snowball is thrown at the block at a velocity of 35 m/s. When the
snowball hits the block, the two of them stick together and the
block/snowball combination begins to slide across the ice
together. How fast it is traveling?

Answer 1

The velocity of block/snowball combination will be 2.1 m/sec. The conservation of momentum principle is employed in the given problem.

What is the law of conservation of momentum?

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁) is the mass of block of ice=  15-kg

(u₁) is the initial velocity of 1st cart (u₁) = 0

(m₂) is the mass of snowball = 3-kg

(u₂) is the initial velocity of snow ball = 35 m/s.

(v) is the velocity after collision =.?

According to the law of conservation of momentum;

Momentum before collision =Momentum after collision

$\rm m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\ 15 \times 0+3 \times 35 = (15+35)\times V\\\\\ V=2.1 \ m/sec$

Hence, the velocity of block/snowball combination will be 2.1 m/sec.

To learn more about the law of conservation of momentum, refer;

https://brainly.com/question/1113396

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