which exponential equation is equivalent to this logarithmic equation?log2x=24
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Reason:
The log equation [tex]\log_{b} (y) = x[/tex] is equivalent to the exponential equation [tex]y = b^x[/tex]
For each equation, the 'b' is the base. Logs are useful to isolate the exponent, and they have other applications as well.
So this is why [tex]\log_2(x) = 24[/tex] turns into [tex]2^{24} = x[/tex]
As another example, [tex]\log_3 (m) = 4[/tex] becomes [tex]m = 3^4[/tex]