Question

Hannah has a chicken coop with six hens. Let X represent the total number of eggs the hens lay on a random day. The distribution for X is given in the table.
A 2-column table with 7 rows. Column 1 is labeled number of eggs with entries 0, 1, 2, 3, 4, 5, 6. Column 2 is labeled probability with entries 0.02, 0.03, 0.07, 0.12, 0.30, 0.28, 0.18.
What is the probability that the hens lay more than two eggs?
0.07
0.12
0.88
0.95

Answer 1

The probability that the hens lay more than two eggs is 0.80

How to determine the probability?

The probability that the hens lay more than two eggs is calculated using:

P(x > 2) = P(3) + P(4) + P(5) + P(6)

Using the data on the table, we have:

P(x > 2) = 0.12 +  0.30 + 0.2 +, 0.18.

Evaluate the sum

P(x > 2) = 0.80

Hence, the probability that the hens lay more than two eggs is 0.80

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