Answer:
Step-by-step explanation:
Let the calculators be C and the books be B.
3C + 4B = 23 and 2C + 3B = 16
3C = 23 - 4B 2(23 - [tex]\frac{4B}{3}[/tex]) + 3B = 16
C = 23 - 4B 46 - [tex]\frac{8B}{3}[/tex] + 3B = 16
3 46 - [tex]\frac{-8B + 3B }{3}[/tex]