Respuesta :

x^2-3x-10=0

(x-5)(x+2) = 0

x-5= 0 so x = 5

x+2 = 0 so x = -2

answer: solutions are x = -2 and x = 5


The solution set of the equation are the truth values of the equation.

The solution set of the equation is {-2,5}

The equation is given as:

[tex]\mathbf{x^2 - 3x - 10 = 0}[/tex]

Expand

[tex]\mathbf{x^2 +2x - 5x - 10 = 0}[/tex]

Factorize

x(x +2) - 5(x + 2) = 0

Factor out x + 2

(x - 5) (x + 2) = 0

Split

(x - 5) = 0 or (x + 2) = 0

Solve for x

x = 5 or x = -2

Hence, the solution set of the equation is {-2,5}

Read more about solution sets at:

https://brainly.com/question/4192789