Respuesta :
x^2-3x-10=0
(x-5)(x+2) = 0
x-5= 0 so x = 5
x+2 = 0 so x = -2
answer: solutions are x = -2 and x = 5
The solution set of the equation are the truth values of the equation.
The solution set of the equation is {-2,5}
The equation is given as:
[tex]\mathbf{x^2 - 3x - 10 = 0}[/tex]
Expand
[tex]\mathbf{x^2 +2x - 5x - 10 = 0}[/tex]
Factorize
x(x +2) - 5(x + 2) = 0
Factor out x + 2
(x - 5) (x + 2) = 0
Split
(x - 5) = 0 or (x + 2) = 0
Solve for x
x = 5 or x = -2
Hence, the solution set of the equation is {-2,5}
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