Question

can someone help with all 4 questions and show work on how to do all of them please

Answer 1

$\\ \rm\Rrightarrow |1/3(2^3-10^2/5)|=|1/3(8-20)|=|1/3(-12)|=4$

$\\ \rm\Rrightarrow |-(1/6)^3|=(1/6)^3=1/216$

$\\ \rm\Rrightarrow |6^3-7^3|=|216-343|=127$

$\\ \rm\Rrightarrow |9^2+(-9)^3|=|81-729|=648$

Answer 2

Answer:

8)  1/216

13)  127

14)  648

15)  4

Step-by-step explanation:

Question 8

$\large \begin{aligned}\displaystyle \left|-\left(\frac{1}{6}\right)^3\right| & = \left|-\left(\frac{1^3}{6^3}\right)\right|\\\\& = \left|-\frac{1}{216}\right|\\\\& = \frac{1}{216}\end{aligned}$

Question 13

$\large \begin{aligned}\displaystyle \left|6^3-7^3\right| & = \left|216-343\\ & = \left|-127\right|\\ & = 127\end{aligned}$

Question 14

$\large \begin{aligned}\displaystyle \left|9^2+(-9)^3\right| & = \left|81+(-729)\right|\\& = \left|81-729\right|\\& = \left|-648\right|\\& = 648\end{aligned}$

Question 15

$\large \begin{aligned}\displaystyle \left|\frac{1}{3}\left(2^3-\frac{10^2}{5}\right)\right| & = \left|\frac{1}{3}\left(8-\frac{100}{5}\right)\right|\\\\& = \left|\frac{1}{3}\left(8-20\right)\right|\\\\& = \left|\frac{1}{3}\left(-12\right)\right|\\\\& = \left|\frac{-12}{3}\right|\\\\& = \left|-4\right|\\\\& = 4\\\end{aligned}$