Answer:
X = [tex]\sqrt{2}[/tex] , Y = 3 , Z = 10
Step-by-step explanation:
using Pythagoras' identity in all 3 right triangles
X² = 1² + 1² = 1 + 1 = 2 ( take square root of both sides )
X = [tex]\sqrt{2}[/tex]
middle triangle
Y² = 1² + X² = 1 + ([tex]\sqrt{2}[/tex] )² = 1 + 2 = 3
triangle on right
Z² = 1² + Y² = 1 + 3² = 1 + 9 = 10
