Question

Determine the electronegativity difference (AEN) and the type of bond formed
(ionic, polar, non-polar).
CF4

Answer 1

the electronegativity difference (AEN):

<0.5: covalent (non polar)

0.5- 1.7: covalent (polar)

> 1.7 : ionic

CF₄

C =  2.5

F = 4

F - C = 4 - 2.5 = 1.5 (covalent polar)

NH₃

N = 3

H = 2.1

N - H = 3 - 2.1 = 0.9 (covalent polar)