Answer:
hypotenuse ≈ 7.6 units
Step-by-step explanation:
calculate the length using the distance formula
d = [tex]\sqrt{(x_{2}-x_{1} )^2+(y_{2}-y_{1})^2 }[/tex]
with (x₁, y₁ ) = (- 1, - 3) and (x₂, y₂ ) = (2, 4) ← endpoints of hypotenuse
d = [tex]\sqrt{(2-(-1))^2+(4-(-3))^2}[/tex]
= [tex]\sqrt{(2+1)^2+(4+3)^2}[/tex]
= [tex]\sqrt{3^2+7^2}[/tex]
= [tex]\sqrt{9+49}[/tex]
= [tex]\sqrt{58}[/tex]
≈ 7.6 ( to the nearest tenth )
